((5x)^2)+7x+2=1

Solution for ((5x)^2)+7x+2=1 equation:

((5x)^2)+7x+2=1

We move all terms to the left:

((5x)^2)+7x+2-(1)=0

determiningTheFunctionDomain
5x^2+7x+2-1=0

We add all the numbers together, and all the variables

5x^2+7x+1=0

a = 5; b = 7; c = +1;
Δ = b2-4ac
Δ = 72-4·5·1
Δ = 29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{29}}{2*5}=\frac{-7-\sqrt{29}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{29}}{2*5}=\frac{-7+\sqrt{29}}{10}
$